PC Pals Forum
General Discussion => The Buzz => Topic started by: Clive on May 22, 2006, 19:48
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Music fans can watch all the action from the upcoming 'Rock in Rio' festival online.
AOL is streaming performances and also offering an on-demand service for the festival, which features dozens of acts, including Guns & Roses, Roger Waters, Shakira, Jamiroquai, The Darkness, Sting, Red Hot Chili Peppers, Anastacia, Kasabian, Carlos Santana, and Corinne Bailey Rae.
'Rock in Rio' is the world's largest and longest running multi-day music festival. Taking place in Lisbon, Portugal over two weekends, 26 ? 27 May and 2 ?4 June, an average of 100,000 people per day will attend the festival.
David Gilbey, vice-president of content and services for AOL UK, said: ?'Rock In Rio' is one of the major global music events in the calendar and the line-up this year is unrivalled, so we're delighted to be able to bring that experience direct into the homes of music fans for the first-time via the internet.?
Gilbey added: ?We proved with our Live 8 webcast that we can deliver major global events on broadband at high quality and in more depth than television broadcasts, as well as offering on-demand access to all the highlights after the show. We know there is significant demand for music online, particularly amongst broadband internet users, and the internet is enabling everyone to get convenient access to the top music festivals for the first time.?
http://www.aol.co.uk/rio
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I'll pass Clive. :D
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but there are some great bands in that lineup:
The Darkness, Red Hot Chili Peppers, Kasabian, Guns & Roses.
but there is some good awful s**te: Anastacia.
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Carlos Santana for me.
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good point, how did i miss...
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I'm off out into the garden with Lona :roll: :) .
Fingers crossed for the tomatoes this year!
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Carlos Santana for me.
Me too! I've seen them three times and they've never been less than astonishing. (https://www.pc-pals.com/smf/proxy.php?request=http%3A%2F%2Fimg.photobucket.com%2Falbums%2Fv300%2FMothballs%2FSmileys%2Fgitpunk.gif&hash=69488ba920b437af5568486cb58b863256779996)